Alexandru Dinu

Male

Târgu-Jiu

Civil Engineering;
(k) = (3 × E × I ) / l3
P0 = PL / (L-x)
L=a1ta + b1tb + c1tsb +d1tad
E = [ L x (g2 - g1) ] / 8
Lm = [ S² × (g2 − g1) ] / 864 ∀ S<Lm
Lm = 2S - [ 864 / (g2 − g1) ] ∀ S>Lm
r = (g2 − g1) / L
R = 5729.58 / D
T = R * tan ( A/2 )
L = 100 * ( A/D )
LC = 2 * R *sin (A/2)
E = R ( (1/(cos (A/2) ) ) - 1 ) )
M = R ( 1 - cos (A/2) )
PC = PI - T
PT = PC + L
L = ( 0.00047hr (fsS) ^2 ) ^ ( 1/3 )
P = 9.93 ( fc^0.5 )( te^2 ) ( ( k / (19000 ( fc^0.5 )( te^3 ) ) ) ^ 0.25
w = 257.876s ( kh / E ) ^ 0.5
Y = L − { L5 / ( 40×R²×Ls²) }
i = L² / ( 6×R×Ls)

Alexandru

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